VM191
VM191
Hertz Contact Between Two Cylinders
Overview
Test Case
Two long cylinders of radii R1 and R2, in frictionless contact with their axes parallel to each other are pressed together with a force per unit length, F. Determine the semi-contact length b and the approach distance d.
Material Properties | Geometric Properties | Loading | |||||||||
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Analysis Assumptions and Modeling Notes
Each analysis uses two load steps; in the first load step a small imposed displacement is used on the upper cylinder to engage contact, whereas in the second load step the imposed displacement is deleted and the force load is applied.
The problem is solved in four different ways:
Contact Algorithm: Augmented Lagrangian - KEYOPT(2) = 0
Contact Algorithm: Lagrange Multiplier - KEYOPT(2) = 3
Plane stress condition is modeled using a unit thickness slice through the cylinders. The region modeled is shown shaded in the problem sketch. The ESURF command is used to automatically generate the contact and target elements between "contactor" nodes on the upper cylinder and "target" nodes on the lower cylinder. The default value of contact stiffness FKN is chosen while performing a solution using Augmented Lagrangian contact algorithm (KEYOPT(2) = 0) whereas no contact stiffness input is required to be specified while performing a solution using Lagrange Multiplier contact algorithm (KEYOPT(2) = 3).
Results Comparison
Target | Mechanical APDL | Ratio | ||
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CONTA175 - Algorithm: Augmented Lagrangian KEYOPT(2) = 0 | ||||
PLANE182 | d,mm | -0.4181 | -0.4219 | 1.009 |
b,mm | 1.20 | 1.1609 | 0.967 | |
SOLID185 | d,mm | -0.4181 | -0.4280 | 1.024 |
b,mm | 1.20 | 1.1609 | 0.967 | |
CONTA175 - Algorithm: Lagrange Multiplier KEYOPT(2) = 3 | ||||
PLANE182 | d,mm | -0.4181 | -0.4181 | 1.000 |
b,mm | 1.20 | 1.1609 | 0.967 | |
SOLID185 | d,mm | -0.4181 | -0.4190 | 1.002 |
b,mm | 1.20 | 1.1609 | 0.967 |